Apostol's Calculus volume 1, 2.13 exercise 16
This is a problem from Apostol's calculus, I have figured out how to find the volume, but not sure about the sketch, what am I supposed to sketch exactly? The problem has not given me what the solid is?
"The cross sections of a solid are squares perpendicular to the x-axis with their centers on the axis. If the square cut off at x has edge $2x^{2}$, find the volume of the solid between $x = 0$ and $x = a$. Make a sketch."
calculus
asked 2 days ago
D. QaD. Qa
344
add a comment |
This is a problem from Apostol's calculus, I have figured out how to find the volume, but not sure about the sketch, what am I supposed to sketch exactly? The problem has not given me what the solid is?
"The cross sections of a solid are squares perpendicular to the x-axis with their centers on the axis. If the square cut off at x has edge $2x^{2}$, find the volume of the solid between $x = 0$ and $x = a$. Make a sketch."
calculus
asked 2 days ago
D. QaD. Qa
344
The problem describes a square pyramid of height $a$ and base of side length $2a^2$ with vertex at the origin and base at $x = a$.
– N. F. Taussig
2 days ago
and by similar triangles I'd get $s= dfrac{L}{h}cdot x= dfrac{2x^{2}}{x} cdot x = 2x^{2}$ ? I don't get how did we know from this problem that the length of the base would be $2x^{2}$?
– D. Qa
17 hours ago
add a comment |
This is a problem from Apostol's calculus, I have figured out how to find the volume, but not sure about the sketch, what am I supposed to sketch exactly? The problem has not given me what the solid is?
"The cross sections of a solid are squares perpendicular to the x-axis with their centers on the axis. If the square cut off at x has edge $2x^{2}$, find the volume of the solid between $x = 0$ and $x = a$. Make a sketch."
calculus
asked 2 days ago
D. QaD. Qa
344
This is a problem from Apostol's calculus, I have figured out how to find the volume, but not sure about the sketch, what am I supposed to sketch exactly? The problem has not given me what the solid is?
"The cross sections of a solid are squares perpendicular to the x-axis with their centers on the axis. If the square cut off at x has edge $2x^{2}$, find the volume of the solid between $x = 0$ and $x = a$. Make a sketch."
calculus
calculus
asked 2 days ago
D. QaD. Qa
344
asked 2 days ago
D. QaD. Qa
344
asked 2 days ago
D. QaD. Qa
344
asked 2 days ago
D. QaD. Qa
344
asked 2 days ago
D. QaD. Qa
344
344
The problem describes a square pyramid of height $a$ and base of side length $2a^2$ with vertex at the origin and base at $x = a$.
– N. F. Taussig
2 days ago
and by similar triangles I'd get $s= dfrac{L}{h}cdot x= dfrac{2x^{2}}{x} cdot x = 2x^{2}$ ? I don't get how did we know from this problem that the length of the base would be $2x^{2}$?
– D. Qa
17 hours ago
add a comment |
The problem describes a square pyramid of height $a$ and base of side length $2a^2$ with vertex at the origin and base at $x = a$.
– N. F. Taussig
2 days ago
and by similar triangles I'd get $s= dfrac{L}{h}cdot x= dfrac{2x^{2}}{x} cdot x = 2x^{2}$ ? I don't get how did we know from this problem that the length of the base would be $2x^{2}$?
– D. Qa
17 hours ago
The problem describes a square pyramid of height $a$ and base of side length $2a^2$ with vertex at the origin and base at $x = a$.
– N. F. Taussig
2 days ago
The problem describes a square pyramid of height $a$ and base of side length $2a^2$ with vertex at the origin and base at $x = a$.
– N. F. Taussig
2 days ago
and by similar triangles I'd get $s= dfrac{L}{h}cdot x= dfrac{2x^{2}}{x} cdot x = 2x^{2}$ ? I don't get how did we know from this problem that the length of the base would be $2x^{2}$?
– D. Qa
17 hours ago
and by similar triangles I'd get $s= dfrac{L}{h}cdot x= dfrac{2x^{2}}{x} cdot x = 2x^{2}$ ? I don't get how did we know from this problem that the length of the base would be $2x^{2}$?
– D. Qa
17 hours ago
add a comment |
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The problem describes a square pyramid of height $a$ and base of side length $2a^2$ with vertex at the origin and base at $x = a$.
– N. F. Taussig
2 days ago
and by similar triangles I'd get $s= dfrac{L}{h}cdot x= dfrac{2x^{2}}{x} cdot x = 2x^{2}$ ? I don't get how did we know from this problem that the length of the base would be $2x^{2}$?
– D. Qa
17 hours ago