What is the inverse Laplace transform of $frac{s^3}{(s+1)^3}$? [closed]
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I tried to expand the given function into partial fractions, but since the degree of numerator and denominator are same, I can't use it.
calculus laplace-transform partial-fractions
edited Jan 21 at 12:02
Daniele Tampieri
2,2922822
asked Jan 21 at 7:47
ZeroisheroZeroishero
1
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closed as off-topic by Shailesh, choco_addicted, mrtaurho, RRL, Trevor Gunn Jan 28 at 16:48
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$begingroup$
I tried to expand the given function into partial fractions, but since the degree of numerator and denominator are same, I can't use it.
calculus laplace-transform partial-fractions
edited Jan 21 at 12:02
Daniele Tampieri
2,2922822
asked Jan 21 at 7:47
ZeroisheroZeroishero
1
$endgroup$
closed as off-topic by Shailesh, choco_addicted, mrtaurho, RRL, Trevor Gunn Jan 28 at 16:48
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Shailesh, choco_addicted, mrtaurho, RRL, Trevor Gunn
If this question can be reworded to fit the rules in the help center, please edit the question.
add a comment |
$begingroup$
I tried to expand the given function into partial fractions, but since the degree of numerator and denominator are same, I can't use it.
calculus laplace-transform partial-fractions
edited Jan 21 at 12:02
Daniele Tampieri
2,2922822
asked Jan 21 at 7:47
ZeroisheroZeroishero
1
$endgroup$
I tried to expand the given function into partial fractions, but since the degree of numerator and denominator are same, I can't use it.
calculus laplace-transform partial-fractions
calculus laplace-transform partial-fractions
edited Jan 21 at 12:02
Daniele Tampieri
2,2922822
asked Jan 21 at 7:47
ZeroisheroZeroishero
1
edited Jan 21 at 12:02
Daniele Tampieri
2,2922822
asked Jan 21 at 7:47
ZeroisheroZeroishero
1
edited Jan 21 at 12:02
Daniele Tampieri
2,2922822
edited Jan 21 at 12:02
Daniele Tampieri
2,2922822
edited Jan 21 at 12:02
Daniele Tampieri
2,2922822
2,2922822
asked Jan 21 at 7:47
ZeroisheroZeroishero
1
asked Jan 21 at 7:47
ZeroisheroZeroishero
1
asked Jan 21 at 7:47
ZeroisheroZeroishero
1
1
closed as off-topic by Shailesh, choco_addicted, mrtaurho, RRL, Trevor Gunn Jan 28 at 16:48
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Shailesh, choco_addicted, mrtaurho, RRL, Trevor Gunn
If this question can be reworded to fit the rules in the help center, please edit the question.
closed as off-topic by Shailesh, choco_addicted, mrtaurho, RRL, Trevor Gunn Jan 28 at 16:48
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Shailesh, choco_addicted, mrtaurho, RRL, Trevor Gunn
If this question can be reworded to fit the rules in the help center, please edit the question.
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1 Answer
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$begingroup$
Hint:
$$dfrac{s^3}{(s-1)^3}=dfrac{(s-1+1)^3}{(s-1)^3}=1+dfrac3{(s-1)^2}+dfrac3{(s-1)}+dfrac1{(s-1)^3}$$
$$L(f(t))=F(s)implies L(e^{at}f(t))=F(s-a)$$
$$L(t^n)=dfrac{n!}{s^{n+1}}$$
answered Jan 21 at 7:51
lab bhattacharjeelab bhattacharjee
226k15157275
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add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Hint:
$$dfrac{s^3}{(s-1)^3}=dfrac{(s-1+1)^3}{(s-1)^3}=1+dfrac3{(s-1)^2}+dfrac3{(s-1)}+dfrac1{(s-1)^3}$$
$$L(f(t))=F(s)implies L(e^{at}f(t))=F(s-a)$$
$$L(t^n)=dfrac{n!}{s^{n+1}}$$
answered Jan 21 at 7:51
lab bhattacharjeelab bhattacharjee
226k15157275
$endgroup$
add a comment |
$begingroup$
Hint:
$$dfrac{s^3}{(s-1)^3}=dfrac{(s-1+1)^3}{(s-1)^3}=1+dfrac3{(s-1)^2}+dfrac3{(s-1)}+dfrac1{(s-1)^3}$$
$$L(f(t))=F(s)implies L(e^{at}f(t))=F(s-a)$$
$$L(t^n)=dfrac{n!}{s^{n+1}}$$
answered Jan 21 at 7:51
lab bhattacharjeelab bhattacharjee
226k15157275
$endgroup$
add a comment |
$begingroup$
Hint:
$$dfrac{s^3}{(s-1)^3}=dfrac{(s-1+1)^3}{(s-1)^3}=1+dfrac3{(s-1)^2}+dfrac3{(s-1)}+dfrac1{(s-1)^3}$$
$$L(f(t))=F(s)implies L(e^{at}f(t))=F(s-a)$$
$$L(t^n)=dfrac{n!}{s^{n+1}}$$
answered Jan 21 at 7:51
lab bhattacharjeelab bhattacharjee
226k15157275
$endgroup$
Hint:
$$dfrac{s^3}{(s-1)^3}=dfrac{(s-1+1)^3}{(s-1)^3}=1+dfrac3{(s-1)^2}+dfrac3{(s-1)}+dfrac1{(s-1)^3}$$
$$L(f(t))=F(s)implies L(e^{at}f(t))=F(s-a)$$
$$L(t^n)=dfrac{n!}{s^{n+1}}$$
answered Jan 21 at 7:51
lab bhattacharjeelab bhattacharjee
226k15157275
answered Jan 21 at 7:51
lab bhattacharjeelab bhattacharjee
226k15157275
answered Jan 21 at 7:51
lab bhattacharjeelab bhattacharjee
226k15157275
answered Jan 21 at 7:51
lab bhattacharjeelab bhattacharjee
226k15157275
226k15157275
add a comment |
add a comment |
