What is the name of this chemical LiB2PO4H7? [duplicate]












-1












$begingroup$



This question already has an answer here:




  • Naming ionic compounds with multiple cations and anions

    1 answer




I was recently looking at a chemical equation calculator that balances equations for you.



enter image description here



I came across a reaction that I am unsure about, it goes like this:



B2H6 + LiH + PO4 = LiB2PO4H7



I was researching the name of the product of this reaction for a while, but couldn't find a name for the chemical. I ask you guys this, if this chemical actually exists, what is the name of it?










share|improve this question











$endgroup$



marked as duplicate by Jon Custer, Todd Minehardt, Mithoron, Tyberius, Nilay Ghosh Jan 8 at 16:27


This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.















  • $begingroup$
    Where did you find this reaction? It's very strange.
    $endgroup$
    – Nicolau Saker Neto
    Jan 8 at 1:08










  • $begingroup$
    I found it on a balancing site.webqc.org/balance.php
    $endgroup$
    – Wither Fang136
    Jan 8 at 1:16










  • $begingroup$
    I don't see the equation on the site. Do you mean you input the chemicals yourself into the calculator, and asked it to balance to see what comes out?
    $endgroup$
    – Nicolau Saker Neto
    Jan 8 at 1:21






  • 7




    $begingroup$
    These websites would accurately balance any BS you feed them with, they don't care about chemistry, only math. What are the reaction conditions (solutions/molten salts/hydrothermal/...)? Where does $ce{PO4^3-}$ come from? If it's phosphoric acid it doesn't make much sense as both diborane and lithium hydride would first react quite violently with water ending up in boric acid and lithium hydroxide. Also, the product seems to be an anion, $ce{LiB2PO4H7-}$, which again doesn't make much sense.
    $endgroup$
    – andselisk
    Jan 8 at 2:05






  • 1




    $begingroup$
    @WitherFang136 arguably the point of having the more general question is to address the large number of specific questions asked on this topic. Since the naming follows general rules, the general question addresses all the specific ones.
    $endgroup$
    – Tyberius
    Jan 8 at 16:12
















-1












$begingroup$



This question already has an answer here:




  • Naming ionic compounds with multiple cations and anions

    1 answer




I was recently looking at a chemical equation calculator that balances equations for you.



enter image description here



I came across a reaction that I am unsure about, it goes like this:



B2H6 + LiH + PO4 = LiB2PO4H7



I was researching the name of the product of this reaction for a while, but couldn't find a name for the chemical. I ask you guys this, if this chemical actually exists, what is the name of it?










share|improve this question











$endgroup$



marked as duplicate by Jon Custer, Todd Minehardt, Mithoron, Tyberius, Nilay Ghosh Jan 8 at 16:27


This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.















  • $begingroup$
    Where did you find this reaction? It's very strange.
    $endgroup$
    – Nicolau Saker Neto
    Jan 8 at 1:08










  • $begingroup$
    I found it on a balancing site.webqc.org/balance.php
    $endgroup$
    – Wither Fang136
    Jan 8 at 1:16










  • $begingroup$
    I don't see the equation on the site. Do you mean you input the chemicals yourself into the calculator, and asked it to balance to see what comes out?
    $endgroup$
    – Nicolau Saker Neto
    Jan 8 at 1:21






  • 7




    $begingroup$
    These websites would accurately balance any BS you feed them with, they don't care about chemistry, only math. What are the reaction conditions (solutions/molten salts/hydrothermal/...)? Where does $ce{PO4^3-}$ come from? If it's phosphoric acid it doesn't make much sense as both diborane and lithium hydride would first react quite violently with water ending up in boric acid and lithium hydroxide. Also, the product seems to be an anion, $ce{LiB2PO4H7-}$, which again doesn't make much sense.
    $endgroup$
    – andselisk
    Jan 8 at 2:05






  • 1




    $begingroup$
    @WitherFang136 arguably the point of having the more general question is to address the large number of specific questions asked on this topic. Since the naming follows general rules, the general question addresses all the specific ones.
    $endgroup$
    – Tyberius
    Jan 8 at 16:12














-1












-1








-1


3



$begingroup$



This question already has an answer here:




  • Naming ionic compounds with multiple cations and anions

    1 answer




I was recently looking at a chemical equation calculator that balances equations for you.



enter image description here



I came across a reaction that I am unsure about, it goes like this:



B2H6 + LiH + PO4 = LiB2PO4H7



I was researching the name of the product of this reaction for a while, but couldn't find a name for the chemical. I ask you guys this, if this chemical actually exists, what is the name of it?










share|improve this question











$endgroup$





This question already has an answer here:




  • Naming ionic compounds with multiple cations and anions

    1 answer




I was recently looking at a chemical equation calculator that balances equations for you.



enter image description here



I came across a reaction that I am unsure about, it goes like this:



B2H6 + LiH + PO4 = LiB2PO4H7



I was researching the name of the product of this reaction for a while, but couldn't find a name for the chemical. I ask you guys this, if this chemical actually exists, what is the name of it?





This question already has an answer here:




  • Naming ionic compounds with multiple cations and anions

    1 answer








inorganic-chemistry nomenclature identification






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Jan 8 at 10:30









user17915

1053




1053










asked Jan 8 at 0:42









Wither Fang136Wither Fang136

1054




1054




marked as duplicate by Jon Custer, Todd Minehardt, Mithoron, Tyberius, Nilay Ghosh Jan 8 at 16:27


This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.






marked as duplicate by Jon Custer, Todd Minehardt, Mithoron, Tyberius, Nilay Ghosh Jan 8 at 16:27


This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.














  • $begingroup$
    Where did you find this reaction? It's very strange.
    $endgroup$
    – Nicolau Saker Neto
    Jan 8 at 1:08










  • $begingroup$
    I found it on a balancing site.webqc.org/balance.php
    $endgroup$
    – Wither Fang136
    Jan 8 at 1:16










  • $begingroup$
    I don't see the equation on the site. Do you mean you input the chemicals yourself into the calculator, and asked it to balance to see what comes out?
    $endgroup$
    – Nicolau Saker Neto
    Jan 8 at 1:21






  • 7




    $begingroup$
    These websites would accurately balance any BS you feed them with, they don't care about chemistry, only math. What are the reaction conditions (solutions/molten salts/hydrothermal/...)? Where does $ce{PO4^3-}$ come from? If it's phosphoric acid it doesn't make much sense as both diborane and lithium hydride would first react quite violently with water ending up in boric acid and lithium hydroxide. Also, the product seems to be an anion, $ce{LiB2PO4H7-}$, which again doesn't make much sense.
    $endgroup$
    – andselisk
    Jan 8 at 2:05






  • 1




    $begingroup$
    @WitherFang136 arguably the point of having the more general question is to address the large number of specific questions asked on this topic. Since the naming follows general rules, the general question addresses all the specific ones.
    $endgroup$
    – Tyberius
    Jan 8 at 16:12


















  • $begingroup$
    Where did you find this reaction? It's very strange.
    $endgroup$
    – Nicolau Saker Neto
    Jan 8 at 1:08










  • $begingroup$
    I found it on a balancing site.webqc.org/balance.php
    $endgroup$
    – Wither Fang136
    Jan 8 at 1:16










  • $begingroup$
    I don't see the equation on the site. Do you mean you input the chemicals yourself into the calculator, and asked it to balance to see what comes out?
    $endgroup$
    – Nicolau Saker Neto
    Jan 8 at 1:21






  • 7




    $begingroup$
    These websites would accurately balance any BS you feed them with, they don't care about chemistry, only math. What are the reaction conditions (solutions/molten salts/hydrothermal/...)? Where does $ce{PO4^3-}$ come from? If it's phosphoric acid it doesn't make much sense as both diborane and lithium hydride would first react quite violently with water ending up in boric acid and lithium hydroxide. Also, the product seems to be an anion, $ce{LiB2PO4H7-}$, which again doesn't make much sense.
    $endgroup$
    – andselisk
    Jan 8 at 2:05






  • 1




    $begingroup$
    @WitherFang136 arguably the point of having the more general question is to address the large number of specific questions asked on this topic. Since the naming follows general rules, the general question addresses all the specific ones.
    $endgroup$
    – Tyberius
    Jan 8 at 16:12
















$begingroup$
Where did you find this reaction? It's very strange.
$endgroup$
– Nicolau Saker Neto
Jan 8 at 1:08




$begingroup$
Where did you find this reaction? It's very strange.
$endgroup$
– Nicolau Saker Neto
Jan 8 at 1:08












$begingroup$
I found it on a balancing site.webqc.org/balance.php
$endgroup$
– Wither Fang136
Jan 8 at 1:16




$begingroup$
I found it on a balancing site.webqc.org/balance.php
$endgroup$
– Wither Fang136
Jan 8 at 1:16












$begingroup$
I don't see the equation on the site. Do you mean you input the chemicals yourself into the calculator, and asked it to balance to see what comes out?
$endgroup$
– Nicolau Saker Neto
Jan 8 at 1:21




$begingroup$
I don't see the equation on the site. Do you mean you input the chemicals yourself into the calculator, and asked it to balance to see what comes out?
$endgroup$
– Nicolau Saker Neto
Jan 8 at 1:21




7




7




$begingroup$
These websites would accurately balance any BS you feed them with, they don't care about chemistry, only math. What are the reaction conditions (solutions/molten salts/hydrothermal/...)? Where does $ce{PO4^3-}$ come from? If it's phosphoric acid it doesn't make much sense as both diborane and lithium hydride would first react quite violently with water ending up in boric acid and lithium hydroxide. Also, the product seems to be an anion, $ce{LiB2PO4H7-}$, which again doesn't make much sense.
$endgroup$
– andselisk
Jan 8 at 2:05




$begingroup$
These websites would accurately balance any BS you feed them with, they don't care about chemistry, only math. What are the reaction conditions (solutions/molten salts/hydrothermal/...)? Where does $ce{PO4^3-}$ come from? If it's phosphoric acid it doesn't make much sense as both diborane and lithium hydride would first react quite violently with water ending up in boric acid and lithium hydroxide. Also, the product seems to be an anion, $ce{LiB2PO4H7-}$, which again doesn't make much sense.
$endgroup$
– andselisk
Jan 8 at 2:05




1




1




$begingroup$
@WitherFang136 arguably the point of having the more general question is to address the large number of specific questions asked on this topic. Since the naming follows general rules, the general question addresses all the specific ones.
$endgroup$
– Tyberius
Jan 8 at 16:12




$begingroup$
@WitherFang136 arguably the point of having the more general question is to address the large number of specific questions asked on this topic. Since the naming follows general rules, the general question addresses all the specific ones.
$endgroup$
– Tyberius
Jan 8 at 16:12










3 Answers
3






active

oldest

votes


















15












$begingroup$

There is an important concept to be understood underlying this question, something all new chemistry students eventually learn: all sensible chemical reactions will balance, but not all equations that balance make chemical sense.



Balancing is purely mathematical manipulation (solving a system of linear equations), and proper balancing is necessary but not sufficient to represent real chemistry.
As a simple example, $ce{200 H2 + O2 -> 2 H200O}$ balances just fine, but doesn't actually mean anything chemically. Here are a few more examples of proposed chemical reactions which balance correctly, but don't actually represent real chemistry due to more subtle arguments.



The crux of the problem is that it is very easy to write a program which can do mathematical balancing of chemical reactions, but it is exceptionally difficult to write a program which can tell in general whether the reaction actually happens! Chemists have spent the past several hundred years tabulating enormous amounts of information (e.g. physical chemistry) and making qualitative descriptions of chemical behaviour (e.g. atomic models, Lewis dot structures, etc.) so we can make this problem tractable after "getting a feel for it".



Okay, back to your reaction. In your particular case, things are made worse by the fact that one of your reagents, $ce{PO4}$, already doesn't exist in any reasonable conditions. Because this is such an unusual chemical, it's hard to predict exactly how it would react based on the rules-of-thumb we know, as most have been developed to understand more "normal" chemistry. What would most likely happen is that it would tear electrons out of just about anything, such as the hydride ions in $ce{LiH}$. The products could end up as a mixture of $ce{Li3PO4}$, $ce{LiBH4}$, $ce{H2}$ and possibly left over reagents, among others.



The closest chemically valid entity to $ce{PO4}$ is the phosphate anion $ce{PO4^3-}$. The calculator you used doesn't understand this by itself, so you would have to write "PO4{3-}" instead of "PO4" in the input field. If you had done this, since $ce{LiH}$ and $ce{B2H6}$ are true, neutral compounds, then any combination of all the above must have a negative charge too (conservation of charge). Nevertheless, I would still expect the online calculator to fail. My basic guess is that the most favourable outcome would be the formation of $ce{LiBH4}$, with other less important side-reactions.






share|improve this answer











$endgroup$









  • 3




    $begingroup$
    And, of course, the website linked in the question happily confirms that $ce{200 H2 + O2 -> 2 H200O}$ is the balanced equation for the synthesis of Nicolau's reagent from hydrogen and oxygen.
    $endgroup$
    – David Richerby
    Jan 8 at 13:28






  • 2




    $begingroup$
    @DavidRicherby Yes, indeed, the prototypical example of dictacoordinate oxygen. With two extra lone pairs.
    $endgroup$
    – Nicolau Saker Neto
    Jan 8 at 13:59



















6












$begingroup$

I've never stumbled upon a "balancing" website that would be checking the correctness of the reaction. This one doesn't even seem to take oxidation state of any element into account as the charges are not balanced (-3 from $ce{PO4^3-}$ on the left and -1 from $ce{LiB2PO4H7^-}$ on the right).



Also, as it's been already ruled out in other answer, these precursors would unlikely result in any borophosphates. However, there is at least one compound characterized that consists of $ce{H,Li,B,O,P}$ only:





  • $ce{Li[B3PO6(OH)3]}$, catena-[monoboro-mono-dihydrogendiboratemonohydrogenphosphate]. Hydrothermal synthesis from $ce{LiOH · 2 H2O}$, $ce{P2O5}$ and $ce{B2O3}$, conc. solution in $ce{HCl}$ at $433~mathrm{K}$ [1].


There is also a few dozens of lithium borophosphates with addenda metals, to name a few:





  • $ce{LiCd(H2O)2[BP2O8] · H2O}$, lithium cadmium diaqua catena-[monoborodiphosphate]- monohydrate. Hydrothermal synthesis from $ce{CdCl2 · 2.5 H2O}$, $ce{LiOH}$, $ce{H3BO3}$ and $85%$ $ce{H3PO4}$ in deionized water at $443~mathrm{K}$ [2].


  • $ce{Li3V2[BP3O12(OH)][HPO4]}$, trilithium divanadium(III) borophosphate hydrogenphosphate. Hydrothermal synthesis from $ce{H3BO3}$, $ce{VCl3}$, $ce{LiH2PO4}$, $ce{LiCl}$ in deionized water at $553~mathrm{K}$ [3].


  • $ce{LiCu2[BP2O8(OH)2]}$, lithium dicopper hihydroxoboro-bis(phosphate(V)). Hydrothermal synthesis from $ce{H3BO3}$, $ce{Cu(OAc)2·H2O}$, $ce{LiH2PO4}$ in deionized water at $473~mathrm{K}$ [4].


As you can see, all methods use less volatile precursors and hydrothermal conditions. Feel free to practice with writing and balancing chemical reactions for these real syntheses.



References




  1. Hauf, C.; Kniep, R. Crystal Structure of Lithium Catena-[Monoboro-Mono-Dihydrogendiboratemonohydrogenphosphate), $ce{Li[B3PO6(OH)3]}$. Zeitschrift für Kristallographie - New Crystal Structures 1997, 212 (1), 313–314. https://doi.org/10.1524/ncrs.1997.212.1.313. (Open Access)

  2. Ge, M.-H.; Mi, J.-X.; Huangm, Y.-X.; Zhao, J.-T.; Kniep, R. Crystal Structure of Lithium Cadmium Diaqua Catena-[Monoborodiphosphate]- Monohydrate, $ce{LiCd(H2O)2[BP2O8] · H2O}$. Zeitschrift für Kristallographie - New Crystal Structures 2003, 218 (JG), 295–296. https://doi.org/10.1524/ncrs.2003.218.jg.295. (Open Access)

  3. Lin, Z.-S.; Hoffmann, S.; Huang, Y.-X.; Prots, Y.; Zhao, J.-T.; Kniep, R. Crystal Structure of Trilithium Divanadium(III) Borophosphate Hydrogenphosphate, $ce{Li3V2[BP3O12(OH)][HPO4]}$. Zeitschrift für Kristallographie - New Crystal Structures 2014, 225 (1), 3–4. https://doi.org/10.1524/ncrs.2010.0002. (Open Access)

  4. Yang, M.; Li, X.; Yu, J.; Zhu, J.; Liu, X.; Chen, G.; Yan, Y. $ce{LiCu2[BP2O8(OH)2]}$: A Chiral Open-Framework Copper Borophosphate via Spontaneous Asymmetrical Crystallization. Dalton Trans. 2013, 42 (18), 6298–6301. https://doi.org/10.1039/C3DT50591J.






share|improve this answer











$endgroup$









  • 1




    $begingroup$
    Why are you saying "1 H on the left"? I see 6 + 1 + 0 which is 7.
    $endgroup$
    – kasperd
    Jan 8 at 9:22






  • 1




    $begingroup$
    @kasperd Because I should've paid more attention when I wrote the answer. Must've been thinking about something else. Thank you, I'm going to fix it.
    $endgroup$
    – andselisk
    Jan 8 at 9:23





















2












$begingroup$

This ion is most likely not the correct product, like the answers say, especially since it is not. However, IUPAC has methods on how to name compounds like these. Take a look at this page in the IUPAC red book.



However, if you were to just name the compound, ignoring the fact that its charge does not balance, you would get something along the lines of:



Lithium diboron phosphate heptahydride.






share|improve this answer









$endgroup$




















    3 Answers
    3






    active

    oldest

    votes








    3 Answers
    3






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    15












    $begingroup$

    There is an important concept to be understood underlying this question, something all new chemistry students eventually learn: all sensible chemical reactions will balance, but not all equations that balance make chemical sense.



    Balancing is purely mathematical manipulation (solving a system of linear equations), and proper balancing is necessary but not sufficient to represent real chemistry.
    As a simple example, $ce{200 H2 + O2 -> 2 H200O}$ balances just fine, but doesn't actually mean anything chemically. Here are a few more examples of proposed chemical reactions which balance correctly, but don't actually represent real chemistry due to more subtle arguments.



    The crux of the problem is that it is very easy to write a program which can do mathematical balancing of chemical reactions, but it is exceptionally difficult to write a program which can tell in general whether the reaction actually happens! Chemists have spent the past several hundred years tabulating enormous amounts of information (e.g. physical chemistry) and making qualitative descriptions of chemical behaviour (e.g. atomic models, Lewis dot structures, etc.) so we can make this problem tractable after "getting a feel for it".



    Okay, back to your reaction. In your particular case, things are made worse by the fact that one of your reagents, $ce{PO4}$, already doesn't exist in any reasonable conditions. Because this is such an unusual chemical, it's hard to predict exactly how it would react based on the rules-of-thumb we know, as most have been developed to understand more "normal" chemistry. What would most likely happen is that it would tear electrons out of just about anything, such as the hydride ions in $ce{LiH}$. The products could end up as a mixture of $ce{Li3PO4}$, $ce{LiBH4}$, $ce{H2}$ and possibly left over reagents, among others.



    The closest chemically valid entity to $ce{PO4}$ is the phosphate anion $ce{PO4^3-}$. The calculator you used doesn't understand this by itself, so you would have to write "PO4{3-}" instead of "PO4" in the input field. If you had done this, since $ce{LiH}$ and $ce{B2H6}$ are true, neutral compounds, then any combination of all the above must have a negative charge too (conservation of charge). Nevertheless, I would still expect the online calculator to fail. My basic guess is that the most favourable outcome would be the formation of $ce{LiBH4}$, with other less important side-reactions.






    share|improve this answer











    $endgroup$









    • 3




      $begingroup$
      And, of course, the website linked in the question happily confirms that $ce{200 H2 + O2 -> 2 H200O}$ is the balanced equation for the synthesis of Nicolau's reagent from hydrogen and oxygen.
      $endgroup$
      – David Richerby
      Jan 8 at 13:28






    • 2




      $begingroup$
      @DavidRicherby Yes, indeed, the prototypical example of dictacoordinate oxygen. With two extra lone pairs.
      $endgroup$
      – Nicolau Saker Neto
      Jan 8 at 13:59
















    15












    $begingroup$

    There is an important concept to be understood underlying this question, something all new chemistry students eventually learn: all sensible chemical reactions will balance, but not all equations that balance make chemical sense.



    Balancing is purely mathematical manipulation (solving a system of linear equations), and proper balancing is necessary but not sufficient to represent real chemistry.
    As a simple example, $ce{200 H2 + O2 -> 2 H200O}$ balances just fine, but doesn't actually mean anything chemically. Here are a few more examples of proposed chemical reactions which balance correctly, but don't actually represent real chemistry due to more subtle arguments.



    The crux of the problem is that it is very easy to write a program which can do mathematical balancing of chemical reactions, but it is exceptionally difficult to write a program which can tell in general whether the reaction actually happens! Chemists have spent the past several hundred years tabulating enormous amounts of information (e.g. physical chemistry) and making qualitative descriptions of chemical behaviour (e.g. atomic models, Lewis dot structures, etc.) so we can make this problem tractable after "getting a feel for it".



    Okay, back to your reaction. In your particular case, things are made worse by the fact that one of your reagents, $ce{PO4}$, already doesn't exist in any reasonable conditions. Because this is such an unusual chemical, it's hard to predict exactly how it would react based on the rules-of-thumb we know, as most have been developed to understand more "normal" chemistry. What would most likely happen is that it would tear electrons out of just about anything, such as the hydride ions in $ce{LiH}$. The products could end up as a mixture of $ce{Li3PO4}$, $ce{LiBH4}$, $ce{H2}$ and possibly left over reagents, among others.



    The closest chemically valid entity to $ce{PO4}$ is the phosphate anion $ce{PO4^3-}$. The calculator you used doesn't understand this by itself, so you would have to write "PO4{3-}" instead of "PO4" in the input field. If you had done this, since $ce{LiH}$ and $ce{B2H6}$ are true, neutral compounds, then any combination of all the above must have a negative charge too (conservation of charge). Nevertheless, I would still expect the online calculator to fail. My basic guess is that the most favourable outcome would be the formation of $ce{LiBH4}$, with other less important side-reactions.






    share|improve this answer











    $endgroup$









    • 3




      $begingroup$
      And, of course, the website linked in the question happily confirms that $ce{200 H2 + O2 -> 2 H200O}$ is the balanced equation for the synthesis of Nicolau's reagent from hydrogen and oxygen.
      $endgroup$
      – David Richerby
      Jan 8 at 13:28






    • 2




      $begingroup$
      @DavidRicherby Yes, indeed, the prototypical example of dictacoordinate oxygen. With two extra lone pairs.
      $endgroup$
      – Nicolau Saker Neto
      Jan 8 at 13:59














    15












    15








    15





    $begingroup$

    There is an important concept to be understood underlying this question, something all new chemistry students eventually learn: all sensible chemical reactions will balance, but not all equations that balance make chemical sense.



    Balancing is purely mathematical manipulation (solving a system of linear equations), and proper balancing is necessary but not sufficient to represent real chemistry.
    As a simple example, $ce{200 H2 + O2 -> 2 H200O}$ balances just fine, but doesn't actually mean anything chemically. Here are a few more examples of proposed chemical reactions which balance correctly, but don't actually represent real chemistry due to more subtle arguments.



    The crux of the problem is that it is very easy to write a program which can do mathematical balancing of chemical reactions, but it is exceptionally difficult to write a program which can tell in general whether the reaction actually happens! Chemists have spent the past several hundred years tabulating enormous amounts of information (e.g. physical chemistry) and making qualitative descriptions of chemical behaviour (e.g. atomic models, Lewis dot structures, etc.) so we can make this problem tractable after "getting a feel for it".



    Okay, back to your reaction. In your particular case, things are made worse by the fact that one of your reagents, $ce{PO4}$, already doesn't exist in any reasonable conditions. Because this is such an unusual chemical, it's hard to predict exactly how it would react based on the rules-of-thumb we know, as most have been developed to understand more "normal" chemistry. What would most likely happen is that it would tear electrons out of just about anything, such as the hydride ions in $ce{LiH}$. The products could end up as a mixture of $ce{Li3PO4}$, $ce{LiBH4}$, $ce{H2}$ and possibly left over reagents, among others.



    The closest chemically valid entity to $ce{PO4}$ is the phosphate anion $ce{PO4^3-}$. The calculator you used doesn't understand this by itself, so you would have to write "PO4{3-}" instead of "PO4" in the input field. If you had done this, since $ce{LiH}$ and $ce{B2H6}$ are true, neutral compounds, then any combination of all the above must have a negative charge too (conservation of charge). Nevertheless, I would still expect the online calculator to fail. My basic guess is that the most favourable outcome would be the formation of $ce{LiBH4}$, with other less important side-reactions.






    share|improve this answer











    $endgroup$



    There is an important concept to be understood underlying this question, something all new chemistry students eventually learn: all sensible chemical reactions will balance, but not all equations that balance make chemical sense.



    Balancing is purely mathematical manipulation (solving a system of linear equations), and proper balancing is necessary but not sufficient to represent real chemistry.
    As a simple example, $ce{200 H2 + O2 -> 2 H200O}$ balances just fine, but doesn't actually mean anything chemically. Here are a few more examples of proposed chemical reactions which balance correctly, but don't actually represent real chemistry due to more subtle arguments.



    The crux of the problem is that it is very easy to write a program which can do mathematical balancing of chemical reactions, but it is exceptionally difficult to write a program which can tell in general whether the reaction actually happens! Chemists have spent the past several hundred years tabulating enormous amounts of information (e.g. physical chemistry) and making qualitative descriptions of chemical behaviour (e.g. atomic models, Lewis dot structures, etc.) so we can make this problem tractable after "getting a feel for it".



    Okay, back to your reaction. In your particular case, things are made worse by the fact that one of your reagents, $ce{PO4}$, already doesn't exist in any reasonable conditions. Because this is such an unusual chemical, it's hard to predict exactly how it would react based on the rules-of-thumb we know, as most have been developed to understand more "normal" chemistry. What would most likely happen is that it would tear electrons out of just about anything, such as the hydride ions in $ce{LiH}$. The products could end up as a mixture of $ce{Li3PO4}$, $ce{LiBH4}$, $ce{H2}$ and possibly left over reagents, among others.



    The closest chemically valid entity to $ce{PO4}$ is the phosphate anion $ce{PO4^3-}$. The calculator you used doesn't understand this by itself, so you would have to write "PO4{3-}" instead of "PO4" in the input field. If you had done this, since $ce{LiH}$ and $ce{B2H6}$ are true, neutral compounds, then any combination of all the above must have a negative charge too (conservation of charge). Nevertheless, I would still expect the online calculator to fail. My basic guess is that the most favourable outcome would be the formation of $ce{LiBH4}$, with other less important side-reactions.







    share|improve this answer














    share|improve this answer



    share|improve this answer








    edited Jan 8 at 3:06

























    answered Jan 8 at 3:01









    Nicolau Saker NetoNicolau Saker Neto

    18.7k35393




    18.7k35393








    • 3




      $begingroup$
      And, of course, the website linked in the question happily confirms that $ce{200 H2 + O2 -> 2 H200O}$ is the balanced equation for the synthesis of Nicolau's reagent from hydrogen and oxygen.
      $endgroup$
      – David Richerby
      Jan 8 at 13:28






    • 2




      $begingroup$
      @DavidRicherby Yes, indeed, the prototypical example of dictacoordinate oxygen. With two extra lone pairs.
      $endgroup$
      – Nicolau Saker Neto
      Jan 8 at 13:59














    • 3




      $begingroup$
      And, of course, the website linked in the question happily confirms that $ce{200 H2 + O2 -> 2 H200O}$ is the balanced equation for the synthesis of Nicolau's reagent from hydrogen and oxygen.
      $endgroup$
      – David Richerby
      Jan 8 at 13:28






    • 2




      $begingroup$
      @DavidRicherby Yes, indeed, the prototypical example of dictacoordinate oxygen. With two extra lone pairs.
      $endgroup$
      – Nicolau Saker Neto
      Jan 8 at 13:59








    3




    3




    $begingroup$
    And, of course, the website linked in the question happily confirms that $ce{200 H2 + O2 -> 2 H200O}$ is the balanced equation for the synthesis of Nicolau's reagent from hydrogen and oxygen.
    $endgroup$
    – David Richerby
    Jan 8 at 13:28




    $begingroup$
    And, of course, the website linked in the question happily confirms that $ce{200 H2 + O2 -> 2 H200O}$ is the balanced equation for the synthesis of Nicolau's reagent from hydrogen and oxygen.
    $endgroup$
    – David Richerby
    Jan 8 at 13:28




    2




    2




    $begingroup$
    @DavidRicherby Yes, indeed, the prototypical example of dictacoordinate oxygen. With two extra lone pairs.
    $endgroup$
    – Nicolau Saker Neto
    Jan 8 at 13:59




    $begingroup$
    @DavidRicherby Yes, indeed, the prototypical example of dictacoordinate oxygen. With two extra lone pairs.
    $endgroup$
    – Nicolau Saker Neto
    Jan 8 at 13:59











    6












    $begingroup$

    I've never stumbled upon a "balancing" website that would be checking the correctness of the reaction. This one doesn't even seem to take oxidation state of any element into account as the charges are not balanced (-3 from $ce{PO4^3-}$ on the left and -1 from $ce{LiB2PO4H7^-}$ on the right).



    Also, as it's been already ruled out in other answer, these precursors would unlikely result in any borophosphates. However, there is at least one compound characterized that consists of $ce{H,Li,B,O,P}$ only:





    • $ce{Li[B3PO6(OH)3]}$, catena-[monoboro-mono-dihydrogendiboratemonohydrogenphosphate]. Hydrothermal synthesis from $ce{LiOH · 2 H2O}$, $ce{P2O5}$ and $ce{B2O3}$, conc. solution in $ce{HCl}$ at $433~mathrm{K}$ [1].


    There is also a few dozens of lithium borophosphates with addenda metals, to name a few:





    • $ce{LiCd(H2O)2[BP2O8] · H2O}$, lithium cadmium diaqua catena-[monoborodiphosphate]- monohydrate. Hydrothermal synthesis from $ce{CdCl2 · 2.5 H2O}$, $ce{LiOH}$, $ce{H3BO3}$ and $85%$ $ce{H3PO4}$ in deionized water at $443~mathrm{K}$ [2].


    • $ce{Li3V2[BP3O12(OH)][HPO4]}$, trilithium divanadium(III) borophosphate hydrogenphosphate. Hydrothermal synthesis from $ce{H3BO3}$, $ce{VCl3}$, $ce{LiH2PO4}$, $ce{LiCl}$ in deionized water at $553~mathrm{K}$ [3].


    • $ce{LiCu2[BP2O8(OH)2]}$, lithium dicopper hihydroxoboro-bis(phosphate(V)). Hydrothermal synthesis from $ce{H3BO3}$, $ce{Cu(OAc)2·H2O}$, $ce{LiH2PO4}$ in deionized water at $473~mathrm{K}$ [4].


    As you can see, all methods use less volatile precursors and hydrothermal conditions. Feel free to practice with writing and balancing chemical reactions for these real syntheses.



    References




    1. Hauf, C.; Kniep, R. Crystal Structure of Lithium Catena-[Monoboro-Mono-Dihydrogendiboratemonohydrogenphosphate), $ce{Li[B3PO6(OH)3]}$. Zeitschrift für Kristallographie - New Crystal Structures 1997, 212 (1), 313–314. https://doi.org/10.1524/ncrs.1997.212.1.313. (Open Access)

    2. Ge, M.-H.; Mi, J.-X.; Huangm, Y.-X.; Zhao, J.-T.; Kniep, R. Crystal Structure of Lithium Cadmium Diaqua Catena-[Monoborodiphosphate]- Monohydrate, $ce{LiCd(H2O)2[BP2O8] · H2O}$. Zeitschrift für Kristallographie - New Crystal Structures 2003, 218 (JG), 295–296. https://doi.org/10.1524/ncrs.2003.218.jg.295. (Open Access)

    3. Lin, Z.-S.; Hoffmann, S.; Huang, Y.-X.; Prots, Y.; Zhao, J.-T.; Kniep, R. Crystal Structure of Trilithium Divanadium(III) Borophosphate Hydrogenphosphate, $ce{Li3V2[BP3O12(OH)][HPO4]}$. Zeitschrift für Kristallographie - New Crystal Structures 2014, 225 (1), 3–4. https://doi.org/10.1524/ncrs.2010.0002. (Open Access)

    4. Yang, M.; Li, X.; Yu, J.; Zhu, J.; Liu, X.; Chen, G.; Yan, Y. $ce{LiCu2[BP2O8(OH)2]}$: A Chiral Open-Framework Copper Borophosphate via Spontaneous Asymmetrical Crystallization. Dalton Trans. 2013, 42 (18), 6298–6301. https://doi.org/10.1039/C3DT50591J.






    share|improve this answer











    $endgroup$









    • 1




      $begingroup$
      Why are you saying "1 H on the left"? I see 6 + 1 + 0 which is 7.
      $endgroup$
      – kasperd
      Jan 8 at 9:22






    • 1




      $begingroup$
      @kasperd Because I should've paid more attention when I wrote the answer. Must've been thinking about something else. Thank you, I'm going to fix it.
      $endgroup$
      – andselisk
      Jan 8 at 9:23


















    6












    $begingroup$

    I've never stumbled upon a "balancing" website that would be checking the correctness of the reaction. This one doesn't even seem to take oxidation state of any element into account as the charges are not balanced (-3 from $ce{PO4^3-}$ on the left and -1 from $ce{LiB2PO4H7^-}$ on the right).



    Also, as it's been already ruled out in other answer, these precursors would unlikely result in any borophosphates. However, there is at least one compound characterized that consists of $ce{H,Li,B,O,P}$ only:





    • $ce{Li[B3PO6(OH)3]}$, catena-[monoboro-mono-dihydrogendiboratemonohydrogenphosphate]. Hydrothermal synthesis from $ce{LiOH · 2 H2O}$, $ce{P2O5}$ and $ce{B2O3}$, conc. solution in $ce{HCl}$ at $433~mathrm{K}$ [1].


    There is also a few dozens of lithium borophosphates with addenda metals, to name a few:





    • $ce{LiCd(H2O)2[BP2O8] · H2O}$, lithium cadmium diaqua catena-[monoborodiphosphate]- monohydrate. Hydrothermal synthesis from $ce{CdCl2 · 2.5 H2O}$, $ce{LiOH}$, $ce{H3BO3}$ and $85%$ $ce{H3PO4}$ in deionized water at $443~mathrm{K}$ [2].


    • $ce{Li3V2[BP3O12(OH)][HPO4]}$, trilithium divanadium(III) borophosphate hydrogenphosphate. Hydrothermal synthesis from $ce{H3BO3}$, $ce{VCl3}$, $ce{LiH2PO4}$, $ce{LiCl}$ in deionized water at $553~mathrm{K}$ [3].


    • $ce{LiCu2[BP2O8(OH)2]}$, lithium dicopper hihydroxoboro-bis(phosphate(V)). Hydrothermal synthesis from $ce{H3BO3}$, $ce{Cu(OAc)2·H2O}$, $ce{LiH2PO4}$ in deionized water at $473~mathrm{K}$ [4].


    As you can see, all methods use less volatile precursors and hydrothermal conditions. Feel free to practice with writing and balancing chemical reactions for these real syntheses.



    References




    1. Hauf, C.; Kniep, R. Crystal Structure of Lithium Catena-[Monoboro-Mono-Dihydrogendiboratemonohydrogenphosphate), $ce{Li[B3PO6(OH)3]}$. Zeitschrift für Kristallographie - New Crystal Structures 1997, 212 (1), 313–314. https://doi.org/10.1524/ncrs.1997.212.1.313. (Open Access)

    2. Ge, M.-H.; Mi, J.-X.; Huangm, Y.-X.; Zhao, J.-T.; Kniep, R. Crystal Structure of Lithium Cadmium Diaqua Catena-[Monoborodiphosphate]- Monohydrate, $ce{LiCd(H2O)2[BP2O8] · H2O}$. Zeitschrift für Kristallographie - New Crystal Structures 2003, 218 (JG), 295–296. https://doi.org/10.1524/ncrs.2003.218.jg.295. (Open Access)

    3. Lin, Z.-S.; Hoffmann, S.; Huang, Y.-X.; Prots, Y.; Zhao, J.-T.; Kniep, R. Crystal Structure of Trilithium Divanadium(III) Borophosphate Hydrogenphosphate, $ce{Li3V2[BP3O12(OH)][HPO4]}$. Zeitschrift für Kristallographie - New Crystal Structures 2014, 225 (1), 3–4. https://doi.org/10.1524/ncrs.2010.0002. (Open Access)

    4. Yang, M.; Li, X.; Yu, J.; Zhu, J.; Liu, X.; Chen, G.; Yan, Y. $ce{LiCu2[BP2O8(OH)2]}$: A Chiral Open-Framework Copper Borophosphate via Spontaneous Asymmetrical Crystallization. Dalton Trans. 2013, 42 (18), 6298–6301. https://doi.org/10.1039/C3DT50591J.






    share|improve this answer











    $endgroup$









    • 1




      $begingroup$
      Why are you saying "1 H on the left"? I see 6 + 1 + 0 which is 7.
      $endgroup$
      – kasperd
      Jan 8 at 9:22






    • 1




      $begingroup$
      @kasperd Because I should've paid more attention when I wrote the answer. Must've been thinking about something else. Thank you, I'm going to fix it.
      $endgroup$
      – andselisk
      Jan 8 at 9:23
















    6












    6








    6





    $begingroup$

    I've never stumbled upon a "balancing" website that would be checking the correctness of the reaction. This one doesn't even seem to take oxidation state of any element into account as the charges are not balanced (-3 from $ce{PO4^3-}$ on the left and -1 from $ce{LiB2PO4H7^-}$ on the right).



    Also, as it's been already ruled out in other answer, these precursors would unlikely result in any borophosphates. However, there is at least one compound characterized that consists of $ce{H,Li,B,O,P}$ only:





    • $ce{Li[B3PO6(OH)3]}$, catena-[monoboro-mono-dihydrogendiboratemonohydrogenphosphate]. Hydrothermal synthesis from $ce{LiOH · 2 H2O}$, $ce{P2O5}$ and $ce{B2O3}$, conc. solution in $ce{HCl}$ at $433~mathrm{K}$ [1].


    There is also a few dozens of lithium borophosphates with addenda metals, to name a few:





    • $ce{LiCd(H2O)2[BP2O8] · H2O}$, lithium cadmium diaqua catena-[monoborodiphosphate]- monohydrate. Hydrothermal synthesis from $ce{CdCl2 · 2.5 H2O}$, $ce{LiOH}$, $ce{H3BO3}$ and $85%$ $ce{H3PO4}$ in deionized water at $443~mathrm{K}$ [2].


    • $ce{Li3V2[BP3O12(OH)][HPO4]}$, trilithium divanadium(III) borophosphate hydrogenphosphate. Hydrothermal synthesis from $ce{H3BO3}$, $ce{VCl3}$, $ce{LiH2PO4}$, $ce{LiCl}$ in deionized water at $553~mathrm{K}$ [3].


    • $ce{LiCu2[BP2O8(OH)2]}$, lithium dicopper hihydroxoboro-bis(phosphate(V)). Hydrothermal synthesis from $ce{H3BO3}$, $ce{Cu(OAc)2·H2O}$, $ce{LiH2PO4}$ in deionized water at $473~mathrm{K}$ [4].


    As you can see, all methods use less volatile precursors and hydrothermal conditions. Feel free to practice with writing and balancing chemical reactions for these real syntheses.



    References




    1. Hauf, C.; Kniep, R. Crystal Structure of Lithium Catena-[Monoboro-Mono-Dihydrogendiboratemonohydrogenphosphate), $ce{Li[B3PO6(OH)3]}$. Zeitschrift für Kristallographie - New Crystal Structures 1997, 212 (1), 313–314. https://doi.org/10.1524/ncrs.1997.212.1.313. (Open Access)

    2. Ge, M.-H.; Mi, J.-X.; Huangm, Y.-X.; Zhao, J.-T.; Kniep, R. Crystal Structure of Lithium Cadmium Diaqua Catena-[Monoborodiphosphate]- Monohydrate, $ce{LiCd(H2O)2[BP2O8] · H2O}$. Zeitschrift für Kristallographie - New Crystal Structures 2003, 218 (JG), 295–296. https://doi.org/10.1524/ncrs.2003.218.jg.295. (Open Access)

    3. Lin, Z.-S.; Hoffmann, S.; Huang, Y.-X.; Prots, Y.; Zhao, J.-T.; Kniep, R. Crystal Structure of Trilithium Divanadium(III) Borophosphate Hydrogenphosphate, $ce{Li3V2[BP3O12(OH)][HPO4]}$. Zeitschrift für Kristallographie - New Crystal Structures 2014, 225 (1), 3–4. https://doi.org/10.1524/ncrs.2010.0002. (Open Access)

    4. Yang, M.; Li, X.; Yu, J.; Zhu, J.; Liu, X.; Chen, G.; Yan, Y. $ce{LiCu2[BP2O8(OH)2]}$: A Chiral Open-Framework Copper Borophosphate via Spontaneous Asymmetrical Crystallization. Dalton Trans. 2013, 42 (18), 6298–6301. https://doi.org/10.1039/C3DT50591J.






    share|improve this answer











    $endgroup$



    I've never stumbled upon a "balancing" website that would be checking the correctness of the reaction. This one doesn't even seem to take oxidation state of any element into account as the charges are not balanced (-3 from $ce{PO4^3-}$ on the left and -1 from $ce{LiB2PO4H7^-}$ on the right).



    Also, as it's been already ruled out in other answer, these precursors would unlikely result in any borophosphates. However, there is at least one compound characterized that consists of $ce{H,Li,B,O,P}$ only:





    • $ce{Li[B3PO6(OH)3]}$, catena-[monoboro-mono-dihydrogendiboratemonohydrogenphosphate]. Hydrothermal synthesis from $ce{LiOH · 2 H2O}$, $ce{P2O5}$ and $ce{B2O3}$, conc. solution in $ce{HCl}$ at $433~mathrm{K}$ [1].


    There is also a few dozens of lithium borophosphates with addenda metals, to name a few:





    • $ce{LiCd(H2O)2[BP2O8] · H2O}$, lithium cadmium diaqua catena-[monoborodiphosphate]- monohydrate. Hydrothermal synthesis from $ce{CdCl2 · 2.5 H2O}$, $ce{LiOH}$, $ce{H3BO3}$ and $85%$ $ce{H3PO4}$ in deionized water at $443~mathrm{K}$ [2].


    • $ce{Li3V2[BP3O12(OH)][HPO4]}$, trilithium divanadium(III) borophosphate hydrogenphosphate. Hydrothermal synthesis from $ce{H3BO3}$, $ce{VCl3}$, $ce{LiH2PO4}$, $ce{LiCl}$ in deionized water at $553~mathrm{K}$ [3].


    • $ce{LiCu2[BP2O8(OH)2]}$, lithium dicopper hihydroxoboro-bis(phosphate(V)). Hydrothermal synthesis from $ce{H3BO3}$, $ce{Cu(OAc)2·H2O}$, $ce{LiH2PO4}$ in deionized water at $473~mathrm{K}$ [4].


    As you can see, all methods use less volatile precursors and hydrothermal conditions. Feel free to practice with writing and balancing chemical reactions for these real syntheses.



    References




    1. Hauf, C.; Kniep, R. Crystal Structure of Lithium Catena-[Monoboro-Mono-Dihydrogendiboratemonohydrogenphosphate), $ce{Li[B3PO6(OH)3]}$. Zeitschrift für Kristallographie - New Crystal Structures 1997, 212 (1), 313–314. https://doi.org/10.1524/ncrs.1997.212.1.313. (Open Access)

    2. Ge, M.-H.; Mi, J.-X.; Huangm, Y.-X.; Zhao, J.-T.; Kniep, R. Crystal Structure of Lithium Cadmium Diaqua Catena-[Monoborodiphosphate]- Monohydrate, $ce{LiCd(H2O)2[BP2O8] · H2O}$. Zeitschrift für Kristallographie - New Crystal Structures 2003, 218 (JG), 295–296. https://doi.org/10.1524/ncrs.2003.218.jg.295. (Open Access)

    3. Lin, Z.-S.; Hoffmann, S.; Huang, Y.-X.; Prots, Y.; Zhao, J.-T.; Kniep, R. Crystal Structure of Trilithium Divanadium(III) Borophosphate Hydrogenphosphate, $ce{Li3V2[BP3O12(OH)][HPO4]}$. Zeitschrift für Kristallographie - New Crystal Structures 2014, 225 (1), 3–4. https://doi.org/10.1524/ncrs.2010.0002. (Open Access)

    4. Yang, M.; Li, X.; Yu, J.; Zhu, J.; Liu, X.; Chen, G.; Yan, Y. $ce{LiCu2[BP2O8(OH)2]}$: A Chiral Open-Framework Copper Borophosphate via Spontaneous Asymmetrical Crystallization. Dalton Trans. 2013, 42 (18), 6298–6301. https://doi.org/10.1039/C3DT50591J.







    share|improve this answer














    share|improve this answer



    share|improve this answer








    edited Jan 8 at 9:24

























    answered Jan 8 at 4:45









    andseliskandselisk

    14.4k649107




    14.4k649107








    • 1




      $begingroup$
      Why are you saying "1 H on the left"? I see 6 + 1 + 0 which is 7.
      $endgroup$
      – kasperd
      Jan 8 at 9:22






    • 1




      $begingroup$
      @kasperd Because I should've paid more attention when I wrote the answer. Must've been thinking about something else. Thank you, I'm going to fix it.
      $endgroup$
      – andselisk
      Jan 8 at 9:23
















    • 1




      $begingroup$
      Why are you saying "1 H on the left"? I see 6 + 1 + 0 which is 7.
      $endgroup$
      – kasperd
      Jan 8 at 9:22






    • 1




      $begingroup$
      @kasperd Because I should've paid more attention when I wrote the answer. Must've been thinking about something else. Thank you, I'm going to fix it.
      $endgroup$
      – andselisk
      Jan 8 at 9:23










    1




    1




    $begingroup$
    Why are you saying "1 H on the left"? I see 6 + 1 + 0 which is 7.
    $endgroup$
    – kasperd
    Jan 8 at 9:22




    $begingroup$
    Why are you saying "1 H on the left"? I see 6 + 1 + 0 which is 7.
    $endgroup$
    – kasperd
    Jan 8 at 9:22




    1




    1




    $begingroup$
    @kasperd Because I should've paid more attention when I wrote the answer. Must've been thinking about something else. Thank you, I'm going to fix it.
    $endgroup$
    – andselisk
    Jan 8 at 9:23






    $begingroup$
    @kasperd Because I should've paid more attention when I wrote the answer. Must've been thinking about something else. Thank you, I'm going to fix it.
    $endgroup$
    – andselisk
    Jan 8 at 9:23













    2












    $begingroup$

    This ion is most likely not the correct product, like the answers say, especially since it is not. However, IUPAC has methods on how to name compounds like these. Take a look at this page in the IUPAC red book.



    However, if you were to just name the compound, ignoring the fact that its charge does not balance, you would get something along the lines of:



    Lithium diboron phosphate heptahydride.






    share|improve this answer









    $endgroup$


















      2












      $begingroup$

      This ion is most likely not the correct product, like the answers say, especially since it is not. However, IUPAC has methods on how to name compounds like these. Take a look at this page in the IUPAC red book.



      However, if you were to just name the compound, ignoring the fact that its charge does not balance, you would get something along the lines of:



      Lithium diboron phosphate heptahydride.






      share|improve this answer









      $endgroup$
















        2












        2








        2





        $begingroup$

        This ion is most likely not the correct product, like the answers say, especially since it is not. However, IUPAC has methods on how to name compounds like these. Take a look at this page in the IUPAC red book.



        However, if you were to just name the compound, ignoring the fact that its charge does not balance, you would get something along the lines of:



        Lithium diboron phosphate heptahydride.






        share|improve this answer









        $endgroup$



        This ion is most likely not the correct product, like the answers say, especially since it is not. However, IUPAC has methods on how to name compounds like these. Take a look at this page in the IUPAC red book.



        However, if you were to just name the compound, ignoring the fact that its charge does not balance, you would get something along the lines of:



        Lithium diboron phosphate heptahydride.







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Jan 8 at 3:42









        chemN00bchemN00b

        519




        519















            Popular posts from this blog

            Mario Kart Wii

            What does “Dominus providebit” mean?

            Antonio Litta Visconti Arese