$X_n$ ~ $Gamma(n,n)$, find the limit in Law of $X_n$












0














I am investigating the following idea.
Let $X_n$ ~ $Gamma(n,n)$. I want to find the limit in Law of this random variable.



I tried using Paul Levy theorem that says the following: If I find the limit of the characteristic function equal to some function $theta(t)$ continuous in 0, then there exists a random variable X such as $X_n to X$ with $theta$ as its characteristic function.



Following this idea I tried calculating the following limit:



$$ lim Big(frac{1}{1-int}Big)^n$$
However to me this goes to 0. But that is not possible because such a characteristic function cannot exist. Is this the right approach?










share|cite|improve this question


















  • 2




    There is another parameterization of $Gamma$ distribution for which $$ varphi_n=(1-it/n)^nto e^{-it}. $$
    – d.k.o.
    Jan 5 at 23:36






  • 1




    Indeed: scale $n$ or $1/n$?
    – Did
    Jan 6 at 0:34










  • @Did What do you mean by scale? Anyway, such a characteristic function is only for the X = 1 constant random variable, am I right?
    – qcc101
    2 days ago










  • "What do you mean by scale?" One of the parameters of every gamma distribution. Please se the WP page, if refreshing your memories is needed.
    – Did
    2 days ago










  • I see. I used the following: $ Big( 1 - frac{it}{n} Big)^{-n}$, but I get $e^{it}$
    – qcc101
    2 days ago
















0














I am investigating the following idea.
Let $X_n$ ~ $Gamma(n,n)$. I want to find the limit in Law of this random variable.



I tried using Paul Levy theorem that says the following: If I find the limit of the characteristic function equal to some function $theta(t)$ continuous in 0, then there exists a random variable X such as $X_n to X$ with $theta$ as its characteristic function.



Following this idea I tried calculating the following limit:



$$ lim Big(frac{1}{1-int}Big)^n$$
However to me this goes to 0. But that is not possible because such a characteristic function cannot exist. Is this the right approach?










share|cite|improve this question


















  • 2




    There is another parameterization of $Gamma$ distribution for which $$ varphi_n=(1-it/n)^nto e^{-it}. $$
    – d.k.o.
    Jan 5 at 23:36






  • 1




    Indeed: scale $n$ or $1/n$?
    – Did
    Jan 6 at 0:34










  • @Did What do you mean by scale? Anyway, such a characteristic function is only for the X = 1 constant random variable, am I right?
    – qcc101
    2 days ago










  • "What do you mean by scale?" One of the parameters of every gamma distribution. Please se the WP page, if refreshing your memories is needed.
    – Did
    2 days ago










  • I see. I used the following: $ Big( 1 - frac{it}{n} Big)^{-n}$, but I get $e^{it}$
    – qcc101
    2 days ago














0












0








0







I am investigating the following idea.
Let $X_n$ ~ $Gamma(n,n)$. I want to find the limit in Law of this random variable.



I tried using Paul Levy theorem that says the following: If I find the limit of the characteristic function equal to some function $theta(t)$ continuous in 0, then there exists a random variable X such as $X_n to X$ with $theta$ as its characteristic function.



Following this idea I tried calculating the following limit:



$$ lim Big(frac{1}{1-int}Big)^n$$
However to me this goes to 0. But that is not possible because such a characteristic function cannot exist. Is this the right approach?










share|cite|improve this question













I am investigating the following idea.
Let $X_n$ ~ $Gamma(n,n)$. I want to find the limit in Law of this random variable.



I tried using Paul Levy theorem that says the following: If I find the limit of the characteristic function equal to some function $theta(t)$ continuous in 0, then there exists a random variable X such as $X_n to X$ with $theta$ as its characteristic function.



Following this idea I tried calculating the following limit:



$$ lim Big(frac{1}{1-int}Big)^n$$
However to me this goes to 0. But that is not possible because such a characteristic function cannot exist. Is this the right approach?







probability limits characteristic-functions






share|cite|improve this question













share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked Jan 5 at 22:34









qcc101qcc101

477113




477113








  • 2




    There is another parameterization of $Gamma$ distribution for which $$ varphi_n=(1-it/n)^nto e^{-it}. $$
    – d.k.o.
    Jan 5 at 23:36






  • 1




    Indeed: scale $n$ or $1/n$?
    – Did
    Jan 6 at 0:34










  • @Did What do you mean by scale? Anyway, such a characteristic function is only for the X = 1 constant random variable, am I right?
    – qcc101
    2 days ago










  • "What do you mean by scale?" One of the parameters of every gamma distribution. Please se the WP page, if refreshing your memories is needed.
    – Did
    2 days ago










  • I see. I used the following: $ Big( 1 - frac{it}{n} Big)^{-n}$, but I get $e^{it}$
    – qcc101
    2 days ago














  • 2




    There is another parameterization of $Gamma$ distribution for which $$ varphi_n=(1-it/n)^nto e^{-it}. $$
    – d.k.o.
    Jan 5 at 23:36






  • 1




    Indeed: scale $n$ or $1/n$?
    – Did
    Jan 6 at 0:34










  • @Did What do you mean by scale? Anyway, such a characteristic function is only for the X = 1 constant random variable, am I right?
    – qcc101
    2 days ago










  • "What do you mean by scale?" One of the parameters of every gamma distribution. Please se the WP page, if refreshing your memories is needed.
    – Did
    2 days ago










  • I see. I used the following: $ Big( 1 - frac{it}{n} Big)^{-n}$, but I get $e^{it}$
    – qcc101
    2 days ago








2




2




There is another parameterization of $Gamma$ distribution for which $$ varphi_n=(1-it/n)^nto e^{-it}. $$
– d.k.o.
Jan 5 at 23:36




There is another parameterization of $Gamma$ distribution for which $$ varphi_n=(1-it/n)^nto e^{-it}. $$
– d.k.o.
Jan 5 at 23:36




1




1




Indeed: scale $n$ or $1/n$?
– Did
Jan 6 at 0:34




Indeed: scale $n$ or $1/n$?
– Did
Jan 6 at 0:34












@Did What do you mean by scale? Anyway, such a characteristic function is only for the X = 1 constant random variable, am I right?
– qcc101
2 days ago




@Did What do you mean by scale? Anyway, such a characteristic function is only for the X = 1 constant random variable, am I right?
– qcc101
2 days ago












"What do you mean by scale?" One of the parameters of every gamma distribution. Please se the WP page, if refreshing your memories is needed.
– Did
2 days ago




"What do you mean by scale?" One of the parameters of every gamma distribution. Please se the WP page, if refreshing your memories is needed.
– Did
2 days ago












I see. I used the following: $ Big( 1 - frac{it}{n} Big)^{-n}$, but I get $e^{it}$
– qcc101
2 days ago




I see. I used the following: $ Big( 1 - frac{it}{n} Big)^{-n}$, but I get $e^{it}$
– qcc101
2 days ago










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