Stuck at an exponential distribution assignment












1














So I have a small question when it comes to probability and the Exponential Distribution.



The assignment states the following:



Clients arrive on a counter independently from one-another. The time between two arrivals has an exponential distribution with a parameter 1/6. Let X be the random variable that defines the time between two arrivals.



One client has just arrived on the counter. Find the probability that the next client will arrive for more than 15 minutes.



I think I know the answer but I'm not sure.



I think I'm suppose to solve P{X>15} but I'm not sure. Is this the right answer?










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  • Do you mean, "will NOT arrive for more than 15 minutes"? If so, the answer is $e^{-15/6}$, which follows directly from the exponential distribution.
    – Math1000
    2 days ago












  • Yes that was what I meant. Is my answer correct?
    – David Mathers
    2 days ago
















1














So I have a small question when it comes to probability and the Exponential Distribution.



The assignment states the following:



Clients arrive on a counter independently from one-another. The time between two arrivals has an exponential distribution with a parameter 1/6. Let X be the random variable that defines the time between two arrivals.



One client has just arrived on the counter. Find the probability that the next client will arrive for more than 15 minutes.



I think I know the answer but I'm not sure.



I think I'm suppose to solve P{X>15} but I'm not sure. Is this the right answer?










share|cite|improve this question






















  • Do you mean, "will NOT arrive for more than 15 minutes"? If so, the answer is $e^{-15/6}$, which follows directly from the exponential distribution.
    – Math1000
    2 days ago












  • Yes that was what I meant. Is my answer correct?
    – David Mathers
    2 days ago














1












1








1







So I have a small question when it comes to probability and the Exponential Distribution.



The assignment states the following:



Clients arrive on a counter independently from one-another. The time between two arrivals has an exponential distribution with a parameter 1/6. Let X be the random variable that defines the time between two arrivals.



One client has just arrived on the counter. Find the probability that the next client will arrive for more than 15 minutes.



I think I know the answer but I'm not sure.



I think I'm suppose to solve P{X>15} but I'm not sure. Is this the right answer?










share|cite|improve this question













So I have a small question when it comes to probability and the Exponential Distribution.



The assignment states the following:



Clients arrive on a counter independently from one-another. The time between two arrivals has an exponential distribution with a parameter 1/6. Let X be the random variable that defines the time between two arrivals.



One client has just arrived on the counter. Find the probability that the next client will arrive for more than 15 minutes.



I think I know the answer but I'm not sure.



I think I'm suppose to solve P{X>15} but I'm not sure. Is this the right answer?







probability






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share|cite|improve this question











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share|cite|improve this question










asked 2 days ago









David MathersDavid Mathers

193




193












  • Do you mean, "will NOT arrive for more than 15 minutes"? If so, the answer is $e^{-15/6}$, which follows directly from the exponential distribution.
    – Math1000
    2 days ago












  • Yes that was what I meant. Is my answer correct?
    – David Mathers
    2 days ago


















  • Do you mean, "will NOT arrive for more than 15 minutes"? If so, the answer is $e^{-15/6}$, which follows directly from the exponential distribution.
    – Math1000
    2 days ago












  • Yes that was what I meant. Is my answer correct?
    – David Mathers
    2 days ago
















Do you mean, "will NOT arrive for more than 15 minutes"? If so, the answer is $e^{-15/6}$, which follows directly from the exponential distribution.
– Math1000
2 days ago






Do you mean, "will NOT arrive for more than 15 minutes"? If so, the answer is $e^{-15/6}$, which follows directly from the exponential distribution.
– Math1000
2 days ago














Yes that was what I meant. Is my answer correct?
– David Mathers
2 days ago




Yes that was what I meant. Is my answer correct?
– David Mathers
2 days ago










1 Answer
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Assuming the events we are concerned about are modeled by means of a random variable X that follows an exponential distribution with rate $lambda=frac{1}{6}$ (which expresses the frequency of arrivals per minute), to find the probability that the time that elapses between the arrival of two clients is greater than 15 minutes, indeed, you need to find $P(X)>15$.



(Although you do not ask about the solution, recall that the cumulative distribution function $F(x)$ of $X$ is given by $1-e^{-lambda,x}$. With that in mind finding the solution is straightforward).






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    1 Answer
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    Assuming the events we are concerned about are modeled by means of a random variable X that follows an exponential distribution with rate $lambda=frac{1}{6}$ (which expresses the frequency of arrivals per minute), to find the probability that the time that elapses between the arrival of two clients is greater than 15 minutes, indeed, you need to find $P(X)>15$.



    (Although you do not ask about the solution, recall that the cumulative distribution function $F(x)$ of $X$ is given by $1-e^{-lambda,x}$. With that in mind finding the solution is straightforward).






    share|cite|improve this answer


























      0














      Assuming the events we are concerned about are modeled by means of a random variable X that follows an exponential distribution with rate $lambda=frac{1}{6}$ (which expresses the frequency of arrivals per minute), to find the probability that the time that elapses between the arrival of two clients is greater than 15 minutes, indeed, you need to find $P(X)>15$.



      (Although you do not ask about the solution, recall that the cumulative distribution function $F(x)$ of $X$ is given by $1-e^{-lambda,x}$. With that in mind finding the solution is straightforward).






      share|cite|improve this answer
























        0












        0








        0






        Assuming the events we are concerned about are modeled by means of a random variable X that follows an exponential distribution with rate $lambda=frac{1}{6}$ (which expresses the frequency of arrivals per minute), to find the probability that the time that elapses between the arrival of two clients is greater than 15 minutes, indeed, you need to find $P(X)>15$.



        (Although you do not ask about the solution, recall that the cumulative distribution function $F(x)$ of $X$ is given by $1-e^{-lambda,x}$. With that in mind finding the solution is straightforward).






        share|cite|improve this answer












        Assuming the events we are concerned about are modeled by means of a random variable X that follows an exponential distribution with rate $lambda=frac{1}{6}$ (which expresses the frequency of arrivals per minute), to find the probability that the time that elapses between the arrival of two clients is greater than 15 minutes, indeed, you need to find $P(X)>15$.



        (Although you do not ask about the solution, recall that the cumulative distribution function $F(x)$ of $X$ is given by $1-e^{-lambda,x}$. With that in mind finding the solution is straightforward).







        share|cite|improve this answer












        share|cite|improve this answer



        share|cite|improve this answer










        answered 2 days ago









        DavidPMDavidPM

        28118




        28118






























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