Shifting roots in infinite sums of polynomials
Define
$$P(n)=(n-r_1)(n-r_2)...(n-r_k)$$
where $r_iinmathbb{Q}$ and $r_ineq r_j$ for $ineq j$. Now, define
$$Q(n)=(n-(r_1+m))(n-r_2)...(n-r_k)$$
where $minmathbb{Z}$ and $r_1+mneq r_j$ for $1<jleq k$. If we know
$$sum_{n=1}^{infty}frac{1}{P(n)}inmathbb{Q}$$
and $r_1+mnotinmathbb{N}$, does that imply
$$sum_{n=1}^{infty}frac{1}{Q(n)}inmathbb{Q}?$$
For example, it can be shown that
$$sum_{n=1}^{infty}frac{1}{(n-frac{1}{2})(n-frac{5}{2})}=-frac{4}{3} text{ while } sum_{n=1}^{infty}frac{1}{(n-(frac{1}{2}+1))(n-frac{5}{2})}=-frac{3}{2}.$$
The motivation for this problem is that I found a link between my last question on this site and this problem. That is, if one could prove this, then they would prove the other question (the easier one about simple roots). Overall, I have tried to work through this problem using residues and generating functions. Any tips, terms, papers, methods, or generally topics that I could look into would also be welcome.
real-analysis generating-functions residue-calculus rationality-testing
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Define
$$P(n)=(n-r_1)(n-r_2)...(n-r_k)$$
where $r_iinmathbb{Q}$ and $r_ineq r_j$ for $ineq j$. Now, define
$$Q(n)=(n-(r_1+m))(n-r_2)...(n-r_k)$$
where $minmathbb{Z}$ and $r_1+mneq r_j$ for $1<jleq k$. If we know
$$sum_{n=1}^{infty}frac{1}{P(n)}inmathbb{Q}$$
and $r_1+mnotinmathbb{N}$, does that imply
$$sum_{n=1}^{infty}frac{1}{Q(n)}inmathbb{Q}?$$
For example, it can be shown that
$$sum_{n=1}^{infty}frac{1}{(n-frac{1}{2})(n-frac{5}{2})}=-frac{4}{3} text{ while } sum_{n=1}^{infty}frac{1}{(n-(frac{1}{2}+1))(n-frac{5}{2})}=-frac{3}{2}.$$
The motivation for this problem is that I found a link between my last question on this site and this problem. That is, if one could prove this, then they would prove the other question (the easier one about simple roots). Overall, I have tried to work through this problem using residues and generating functions. Any tips, terms, papers, methods, or generally topics that I could look into would also be welcome.
real-analysis generating-functions residue-calculus rationality-testing
add a comment |
Define
$$P(n)=(n-r_1)(n-r_2)...(n-r_k)$$
where $r_iinmathbb{Q}$ and $r_ineq r_j$ for $ineq j$. Now, define
$$Q(n)=(n-(r_1+m))(n-r_2)...(n-r_k)$$
where $minmathbb{Z}$ and $r_1+mneq r_j$ for $1<jleq k$. If we know
$$sum_{n=1}^{infty}frac{1}{P(n)}inmathbb{Q}$$
and $r_1+mnotinmathbb{N}$, does that imply
$$sum_{n=1}^{infty}frac{1}{Q(n)}inmathbb{Q}?$$
For example, it can be shown that
$$sum_{n=1}^{infty}frac{1}{(n-frac{1}{2})(n-frac{5}{2})}=-frac{4}{3} text{ while } sum_{n=1}^{infty}frac{1}{(n-(frac{1}{2}+1))(n-frac{5}{2})}=-frac{3}{2}.$$
The motivation for this problem is that I found a link between my last question on this site and this problem. That is, if one could prove this, then they would prove the other question (the easier one about simple roots). Overall, I have tried to work through this problem using residues and generating functions. Any tips, terms, papers, methods, or generally topics that I could look into would also be welcome.
real-analysis generating-functions residue-calculus rationality-testing
Define
$$P(n)=(n-r_1)(n-r_2)...(n-r_k)$$
where $r_iinmathbb{Q}$ and $r_ineq r_j$ for $ineq j$. Now, define
$$Q(n)=(n-(r_1+m))(n-r_2)...(n-r_k)$$
where $minmathbb{Z}$ and $r_1+mneq r_j$ for $1<jleq k$. If we know
$$sum_{n=1}^{infty}frac{1}{P(n)}inmathbb{Q}$$
and $r_1+mnotinmathbb{N}$, does that imply
$$sum_{n=1}^{infty}frac{1}{Q(n)}inmathbb{Q}?$$
For example, it can be shown that
$$sum_{n=1}^{infty}frac{1}{(n-frac{1}{2})(n-frac{5}{2})}=-frac{4}{3} text{ while } sum_{n=1}^{infty}frac{1}{(n-(frac{1}{2}+1))(n-frac{5}{2})}=-frac{3}{2}.$$
The motivation for this problem is that I found a link between my last question on this site and this problem. That is, if one could prove this, then they would prove the other question (the easier one about simple roots). Overall, I have tried to work through this problem using residues and generating functions. Any tips, terms, papers, methods, or generally topics that I could look into would also be welcome.
real-analysis generating-functions residue-calculus rationality-testing
real-analysis generating-functions residue-calculus rationality-testing
asked 2 days ago
Nick GuerreroNick Guerrero
537411
537411
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