proving property of differential forms












1












$begingroup$


Let be
$ omega $ and $ zeta $ differential forms of $C^{(1)} $ on the open set $G subset mathbb{R}^n $



and $ omega $ is of rank $r$



How to prove that following property is true:



$$ d( omega wedge zeta )= domega wedge zeta + (-1)^r omega wedge dzeta. $$



differential forms are quite hard to unterstand and handle for me ..I would appreciate any help !










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$endgroup$












  • $begingroup$
    Possible duplicate: math.stackexchange.com/questions/1164823/…
    $endgroup$
    – T. Ford
    Jan 8 at 22:14










  • $begingroup$
    Known as the 'product rule for the wedge product' I believe.. ?
    $endgroup$
    – T. Ford
    Jan 8 at 22:15
















1












$begingroup$


Let be
$ omega $ and $ zeta $ differential forms of $C^{(1)} $ on the open set $G subset mathbb{R}^n $



and $ omega $ is of rank $r$



How to prove that following property is true:



$$ d( omega wedge zeta )= domega wedge zeta + (-1)^r omega wedge dzeta. $$



differential forms are quite hard to unterstand and handle for me ..I would appreciate any help !










share|cite|improve this question









$endgroup$












  • $begingroup$
    Possible duplicate: math.stackexchange.com/questions/1164823/…
    $endgroup$
    – T. Ford
    Jan 8 at 22:14










  • $begingroup$
    Known as the 'product rule for the wedge product' I believe.. ?
    $endgroup$
    – T. Ford
    Jan 8 at 22:15














1












1








1





$begingroup$


Let be
$ omega $ and $ zeta $ differential forms of $C^{(1)} $ on the open set $G subset mathbb{R}^n $



and $ omega $ is of rank $r$



How to prove that following property is true:



$$ d( omega wedge zeta )= domega wedge zeta + (-1)^r omega wedge dzeta. $$



differential forms are quite hard to unterstand and handle for me ..I would appreciate any help !










share|cite|improve this question









$endgroup$




Let be
$ omega $ and $ zeta $ differential forms of $C^{(1)} $ on the open set $G subset mathbb{R}^n $



and $ omega $ is of rank $r$



How to prove that following property is true:



$$ d( omega wedge zeta )= domega wedge zeta + (-1)^r omega wedge dzeta. $$



differential forms are quite hard to unterstand and handle for me ..I would appreciate any help !







real-analysis differential-geometry differential-forms






share|cite|improve this question













share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked Jan 8 at 22:05









wondering1123wondering1123

13711




13711












  • $begingroup$
    Possible duplicate: math.stackexchange.com/questions/1164823/…
    $endgroup$
    – T. Ford
    Jan 8 at 22:14










  • $begingroup$
    Known as the 'product rule for the wedge product' I believe.. ?
    $endgroup$
    – T. Ford
    Jan 8 at 22:15


















  • $begingroup$
    Possible duplicate: math.stackexchange.com/questions/1164823/…
    $endgroup$
    – T. Ford
    Jan 8 at 22:14










  • $begingroup$
    Known as the 'product rule for the wedge product' I believe.. ?
    $endgroup$
    – T. Ford
    Jan 8 at 22:15
















$begingroup$
Possible duplicate: math.stackexchange.com/questions/1164823/…
$endgroup$
– T. Ford
Jan 8 at 22:14




$begingroup$
Possible duplicate: math.stackexchange.com/questions/1164823/…
$endgroup$
– T. Ford
Jan 8 at 22:14












$begingroup$
Known as the 'product rule for the wedge product' I believe.. ?
$endgroup$
– T. Ford
Jan 8 at 22:15




$begingroup$
Known as the 'product rule for the wedge product' I believe.. ?
$endgroup$
– T. Ford
Jan 8 at 22:15










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