Help with simplifying a trigonometric expression












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Could anyone help simplify this expression,
$$dfrac{sin^{(-1)}left(dfrac{sin(90)sqrt{frac1{pi}-0.25}}{sqrt{frac1{pi}}}right)}{360}-0.5sqrt{frac1{pi}-0.25}
$$



It's in degrees.










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    Welcome the Mathematics Stack Exchange community. A quick tour of the site will help you get the most of your time here. For typesetting your equations, please use MathJax. Here is a great reference.
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    – dantopa
    Jan 9 at 22:53
















0












$begingroup$


Could anyone help simplify this expression,
$$dfrac{sin^{(-1)}left(dfrac{sin(90)sqrt{frac1{pi}-0.25}}{sqrt{frac1{pi}}}right)}{360}-0.5sqrt{frac1{pi}-0.25}
$$



It's in degrees.










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  • $begingroup$
    Welcome the Mathematics Stack Exchange community. A quick tour of the site will help you get the most of your time here. For typesetting your equations, please use MathJax. Here is a great reference.
    $endgroup$
    – dantopa
    Jan 9 at 22:53














0












0








0





$begingroup$


Could anyone help simplify this expression,
$$dfrac{sin^{(-1)}left(dfrac{sin(90)sqrt{frac1{pi}-0.25}}{sqrt{frac1{pi}}}right)}{360}-0.5sqrt{frac1{pi}-0.25}
$$



It's in degrees.










share|cite|improve this question











$endgroup$




Could anyone help simplify this expression,
$$dfrac{sin^{(-1)}left(dfrac{sin(90)sqrt{frac1{pi}-0.25}}{sqrt{frac1{pi}}}right)}{360}-0.5sqrt{frac1{pi}-0.25}
$$



It's in degrees.







trigonometry






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edited Jan 9 at 23:17







L. Kohler

















asked Jan 9 at 22:40









L. KohlerL. Kohler

11




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  • $begingroup$
    Welcome the Mathematics Stack Exchange community. A quick tour of the site will help you get the most of your time here. For typesetting your equations, please use MathJax. Here is a great reference.
    $endgroup$
    – dantopa
    Jan 9 at 22:53


















  • $begingroup$
    Welcome the Mathematics Stack Exchange community. A quick tour of the site will help you get the most of your time here. For typesetting your equations, please use MathJax. Here is a great reference.
    $endgroup$
    – dantopa
    Jan 9 at 22:53
















$begingroup$
Welcome the Mathematics Stack Exchange community. A quick tour of the site will help you get the most of your time here. For typesetting your equations, please use MathJax. Here is a great reference.
$endgroup$
– dantopa
Jan 9 at 22:53




$begingroup$
Welcome the Mathematics Stack Exchange community. A quick tour of the site will help you get the most of your time here. For typesetting your equations, please use MathJax. Here is a great reference.
$endgroup$
– dantopa
Jan 9 at 22:53










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$begingroup$

$begin{array}\
dfrac{arcsinleft(dfrac{sin(90)sqrt{frac1{pi}-0.25}}{sqrt{frac1{pi}}}right)}{360}-0.5sqrt{frac1{pi}-0.25}
&=dfrac{arcsinleft(dfrac{sqrt{frac1{pi}-0.25}}{sqrt{frac1{pi}}}right)}{2pi}-0.5sqrt{frac1{pi}-0.25}
qquadtext{converting to radians}\
&=dfrac{arcsinleft(sqrt{1-pi/4}right)}{2pi}-0.5sqrt{frac1{pi}-0.25}\
\
&=-0.054022154...
qquadtext{according to Wolfy}\
end{array}
$






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    1 Answer
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    $begingroup$

    $begin{array}\
    dfrac{arcsinleft(dfrac{sin(90)sqrt{frac1{pi}-0.25}}{sqrt{frac1{pi}}}right)}{360}-0.5sqrt{frac1{pi}-0.25}
    &=dfrac{arcsinleft(dfrac{sqrt{frac1{pi}-0.25}}{sqrt{frac1{pi}}}right)}{2pi}-0.5sqrt{frac1{pi}-0.25}
    qquadtext{converting to radians}\
    &=dfrac{arcsinleft(sqrt{1-pi/4}right)}{2pi}-0.5sqrt{frac1{pi}-0.25}\
    \
    &=-0.054022154...
    qquadtext{according to Wolfy}\
    end{array}
    $






    share|cite|improve this answer









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      0












      $begingroup$

      $begin{array}\
      dfrac{arcsinleft(dfrac{sin(90)sqrt{frac1{pi}-0.25}}{sqrt{frac1{pi}}}right)}{360}-0.5sqrt{frac1{pi}-0.25}
      &=dfrac{arcsinleft(dfrac{sqrt{frac1{pi}-0.25}}{sqrt{frac1{pi}}}right)}{2pi}-0.5sqrt{frac1{pi}-0.25}
      qquadtext{converting to radians}\
      &=dfrac{arcsinleft(sqrt{1-pi/4}right)}{2pi}-0.5sqrt{frac1{pi}-0.25}\
      \
      &=-0.054022154...
      qquadtext{according to Wolfy}\
      end{array}
      $






      share|cite|improve this answer









      $endgroup$
















        0












        0








        0





        $begingroup$

        $begin{array}\
        dfrac{arcsinleft(dfrac{sin(90)sqrt{frac1{pi}-0.25}}{sqrt{frac1{pi}}}right)}{360}-0.5sqrt{frac1{pi}-0.25}
        &=dfrac{arcsinleft(dfrac{sqrt{frac1{pi}-0.25}}{sqrt{frac1{pi}}}right)}{2pi}-0.5sqrt{frac1{pi}-0.25}
        qquadtext{converting to radians}\
        &=dfrac{arcsinleft(sqrt{1-pi/4}right)}{2pi}-0.5sqrt{frac1{pi}-0.25}\
        \
        &=-0.054022154...
        qquadtext{according to Wolfy}\
        end{array}
        $






        share|cite|improve this answer









        $endgroup$



        $begin{array}\
        dfrac{arcsinleft(dfrac{sin(90)sqrt{frac1{pi}-0.25}}{sqrt{frac1{pi}}}right)}{360}-0.5sqrt{frac1{pi}-0.25}
        &=dfrac{arcsinleft(dfrac{sqrt{frac1{pi}-0.25}}{sqrt{frac1{pi}}}right)}{2pi}-0.5sqrt{frac1{pi}-0.25}
        qquadtext{converting to radians}\
        &=dfrac{arcsinleft(sqrt{1-pi/4}right)}{2pi}-0.5sqrt{frac1{pi}-0.25}\
        \
        &=-0.054022154...
        qquadtext{according to Wolfy}\
        end{array}
        $







        share|cite|improve this answer












        share|cite|improve this answer



        share|cite|improve this answer










        answered Jan 9 at 22:59









        marty cohenmarty cohen

        73.1k549128




        73.1k549128






























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