Proof of homogeneous Markov chain and state-transition matrix












1














Let $X_i$ be the results of a consecutive throws of a dice. Let $Z_n=3(X_1^2+...+X_n^2) mod 5$. Show that the sequence ${{Z_n | ngeq1}}$ is a homogeneous Markov Chain. Find a state space and a state-trasition matrix.





I know the Markov chain property which is



$P(X_n=s | X_0=x_0,...,X_{n-1}=x_{n-1}) = P(X_n=s|X_{n-1}=x_{n-1})$ and then the Markov chain is homogeneous, when



$P(X_{n+1}=j|X_n=i)=P(X_1=j|X_0=i)$



We know that $X_1,...,X_n$ are independent so



$P(X_n=s | X_0=x_0,...,X_{n-1}=x_{n-1})=P(X_n=s)$ and $P(X_n=s|X_{n-1}=x_{n-1})=P(X_n=s)$ hence $P(X_{n+1}=j)=P(X_1=j)$,
but from this point I don't know how to continue.



Any help will be much appreciated.










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    1














    Let $X_i$ be the results of a consecutive throws of a dice. Let $Z_n=3(X_1^2+...+X_n^2) mod 5$. Show that the sequence ${{Z_n | ngeq1}}$ is a homogeneous Markov Chain. Find a state space and a state-trasition matrix.





    I know the Markov chain property which is



    $P(X_n=s | X_0=x_0,...,X_{n-1}=x_{n-1}) = P(X_n=s|X_{n-1}=x_{n-1})$ and then the Markov chain is homogeneous, when



    $P(X_{n+1}=j|X_n=i)=P(X_1=j|X_0=i)$



    We know that $X_1,...,X_n$ are independent so



    $P(X_n=s | X_0=x_0,...,X_{n-1}=x_{n-1})=P(X_n=s)$ and $P(X_n=s|X_{n-1}=x_{n-1})=P(X_n=s)$ hence $P(X_{n+1}=j)=P(X_1=j)$,
    but from this point I don't know how to continue.



    Any help will be much appreciated.










    share|cite|improve this question



























      1












      1








      1







      Let $X_i$ be the results of a consecutive throws of a dice. Let $Z_n=3(X_1^2+...+X_n^2) mod 5$. Show that the sequence ${{Z_n | ngeq1}}$ is a homogeneous Markov Chain. Find a state space and a state-trasition matrix.





      I know the Markov chain property which is



      $P(X_n=s | X_0=x_0,...,X_{n-1}=x_{n-1}) = P(X_n=s|X_{n-1}=x_{n-1})$ and then the Markov chain is homogeneous, when



      $P(X_{n+1}=j|X_n=i)=P(X_1=j|X_0=i)$



      We know that $X_1,...,X_n$ are independent so



      $P(X_n=s | X_0=x_0,...,X_{n-1}=x_{n-1})=P(X_n=s)$ and $P(X_n=s|X_{n-1}=x_{n-1})=P(X_n=s)$ hence $P(X_{n+1}=j)=P(X_1=j)$,
      but from this point I don't know how to continue.



      Any help will be much appreciated.










      share|cite|improve this question















      Let $X_i$ be the results of a consecutive throws of a dice. Let $Z_n=3(X_1^2+...+X_n^2) mod 5$. Show that the sequence ${{Z_n | ngeq1}}$ is a homogeneous Markov Chain. Find a state space and a state-trasition matrix.





      I know the Markov chain property which is



      $P(X_n=s | X_0=x_0,...,X_{n-1}=x_{n-1}) = P(X_n=s|X_{n-1}=x_{n-1})$ and then the Markov chain is homogeneous, when



      $P(X_{n+1}=j|X_n=i)=P(X_1=j|X_0=i)$



      We know that $X_1,...,X_n$ are independent so



      $P(X_n=s | X_0=x_0,...,X_{n-1}=x_{n-1})=P(X_n=s)$ and $P(X_n=s|X_{n-1}=x_{n-1})=P(X_n=s)$ hence $P(X_{n+1}=j)=P(X_1=j)$,
      but from this point I don't know how to continue.



      Any help will be much appreciated.







      probability-theory stochastic-processes markov-chains






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      edited 2 days ago







      MacAbra

















      asked Dec 15 '18 at 12:25









      MacAbraMacAbra

      17519




      17519






















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