Greatest Integer(floor function) integral [on hold]
-2
What is this integral equal to ?
$$int_0^a lfloor{x^n}rfloor$$
calculus definite-integrals floor-function
asked 2 days ago
Pratyay MishraPratyay Mishra
4
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put on hold as off-topic by amWhy, Martin R, Math1000, Davide Giraudo, Abcd 2 days ago
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – amWhy, Martin R, Math1000, Davide Giraudo, Abcd
If this question can be reworded to fit the rules in the help center, please edit the question.
add a comment |
-2
What is this integral equal to ?
$$int_0^a lfloor{x^n}rfloor$$
calculus definite-integrals floor-function
asked 2 days ago
Pratyay MishraPratyay Mishra
4
New contributor
Pratyay Mishra is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
put on hold as off-topic by amWhy, Martin R, Math1000, Davide Giraudo, Abcd 2 days ago
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – amWhy, Martin R, Math1000, Davide Giraudo, Abcd
If this question can be reworded to fit the rules in the help center, please edit the question.
Welcome to math.SE!! What have you tried? How are defined $a$ and $n$? From what variable must we integrate?
– manooooh
2 days ago
n is a natural no.'a' is just a rational no.x is the integration variable.I wrote it as x^n - frac(x^n) and then tried to integrate.The 1st part can be integrated directly and the second part is periodic(0,1). I get answer as (x^(n+1)-frac(x)^(n+1)-1)/(n+1). But the answer in the book does not match mine.
– Pratyay Mishra
2 days ago
No, "the second part" is not periodic. Look sharper.
– metamorphy
2 days ago
add a comment |
-2
-2
-2
What is this integral equal to ?
$$int_0^a lfloor{x^n}rfloor$$
calculus definite-integrals floor-function
asked 2 days ago
Pratyay MishraPratyay Mishra
4
New contributor
Pratyay Mishra is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
What is this integral equal to ?
$$int_0^a lfloor{x^n}rfloor$$
calculus definite-integrals floor-function
calculus definite-integrals floor-function
asked 2 days ago
Pratyay MishraPratyay Mishra
4
New contributor
Pratyay Mishra is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 2 days ago
Pratyay MishraPratyay Mishra
4
New contributor
Pratyay Mishra is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 2 days ago
Pratyay MishraPratyay Mishra
4
New contributor
Pratyay Mishra is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 2 days ago
Pratyay MishraPratyay Mishra
4
asked 2 days ago
Pratyay MishraPratyay Mishra
4
4
New contributor
Pratyay Mishra is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Pratyay Mishra is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Pratyay Mishra is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
put on hold as off-topic by amWhy, Martin R, Math1000, Davide Giraudo, Abcd 2 days ago
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – amWhy, Martin R, Math1000, Davide Giraudo, Abcd
If this question can be reworded to fit the rules in the help center, please edit the question.
put on hold as off-topic by amWhy, Martin R, Math1000, Davide Giraudo, Abcd 2 days ago
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – amWhy, Martin R, Math1000, Davide Giraudo, Abcd
If this question can be reworded to fit the rules in the help center, please edit the question.
Welcome to math.SE!! What have you tried? How are defined $a$ and $n$? From what variable must we integrate?
– manooooh
2 days ago
n is a natural no.'a' is just a rational no.x is the integration variable.I wrote it as x^n - frac(x^n) and then tried to integrate.The 1st part can be integrated directly and the second part is periodic(0,1). I get answer as (x^(n+1)-frac(x)^(n+1)-1)/(n+1). But the answer in the book does not match mine.
– Pratyay Mishra
2 days ago
No, "the second part" is not periodic. Look sharper.
– metamorphy
2 days ago
add a comment |
Welcome to math.SE!! What have you tried? How are defined $a$ and $n$? From what variable must we integrate?
– manooooh
2 days ago
n is a natural no.'a' is just a rational no.x is the integration variable.I wrote it as x^n - frac(x^n) and then tried to integrate.The 1st part can be integrated directly and the second part is periodic(0,1). I get answer as (x^(n+1)-frac(x)^(n+1)-1)/(n+1). But the answer in the book does not match mine.
– Pratyay Mishra
2 days ago
No, "the second part" is not periodic. Look sharper.
– metamorphy
2 days ago
Welcome to math.SE!! What have you tried? How are defined $a$ and $n$? From what variable must we integrate?
– manooooh
2 days ago
Welcome to math.SE!! What have you tried? How are defined $a$ and $n$? From what variable must we integrate?
– manooooh
2 days ago
n is a natural no.'a' is just a rational no.x is the integration variable.I wrote it as x^n - frac(x^n) and then tried to integrate.The 1st part can be integrated directly and the second part is periodic(0,1). I get answer as (x^(n+1)-frac(x)^(n+1)-1)/(n+1). But the answer in the book does not match mine.
– Pratyay Mishra
2 days ago
n is a natural no.'a' is just a rational no.x is the integration variable.I wrote it as x^n - frac(x^n) and then tried to integrate.The 1st part can be integrated directly and the second part is periodic(0,1). I get answer as (x^(n+1)-frac(x)^(n+1)-1)/(n+1). But the answer in the book does not match mine.
– Pratyay Mishra
2 days ago
No, "the second part" is not periodic. Look sharper.
– metamorphy
2 days ago
No, "the second part" is not periodic. Look sharper.
– metamorphy
2 days ago
add a comment |
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Welcome to math.SE!! What have you tried? How are defined $a$ and $n$? From what variable must we integrate?
– manooooh
2 days ago
n is a natural no.'a' is just a rational no.x is the integration variable.I wrote it as x^n - frac(x^n) and then tried to integrate.The 1st part can be integrated directly and the second part is periodic(0,1). I get answer as (x^(n+1)-frac(x)^(n+1)-1)/(n+1). But the answer in the book does not match mine.
– Pratyay Mishra
2 days ago
No, "the second part" is not periodic. Look sharper.
– metamorphy
2 days ago